連立不等式(2次)
次の連立不等式を解け
{x2−4x−5<0x2+x−6≧0 2≦x<5 {x2+5x−24<0x2−4x−12<0 −2<x<3 {x2−4x−32≦0x2−2x≦0 0≦x≦2 {x2−7x+10>0x2−7x+12≧0 x<2, 5<x {x2+9x+18≦0x2+3x+2>0 −6≦x≦−3 {x2−4x−12≦0x2−4x>0 −2≦x<0, 4<x≦6 {x2−7x+6≧0x2−x−12>0 x<−3, 6≦x {x2+7x+10>0x2−5x+4≧0 x<−5, −2<x≦1, 4≦x
次の連立不等式を解け
{x2−x≧0x2+4x−2<0 −2−6<x≦0 {x2+2x−1<06x2−x−15≦0 −32 ≦x<−1+2 {x2−2x−14>0x2−x−12≧0 x≦−3, 1+15<x {x2+6x+7≧0x2−2x−5>0 x≦−3−2 , −3+2≦x<1−6, 1+6<x